Web在三角形ABC中,sinC (cosA+cosB)=sinA+sinB.求∠C的度数;若角C所对的边c=1,求内切圆半径r 1年前 2个回答 在三角形ABC中,A,B为锐角,sinA=5分之根号5,sinB=10分之根号10.若a-b=根号2-1 1年前 1个回答 在Rt ABC中角c=90°利用sinB=b分之c.cosB=c分之a证明对于同个锐角的正,余弦之间sinB*sinB+ 1年前 1个回答 在 ABC中,已 … Web18 okt. 2024 · plug above values into the general formula for sine of sum of 2 angles sin (A+B) = sinAcosB + sinBcosA sin (A+B) = (2/3) (2sqr2)/3 + (1/3)sqr5/3 = (4/3)sqr2/3 + …
TRIGONOMETRIC FUNCTIONS-II - National Institute of Open …
Web【解析】sinA+sinB+sinC=2 sin (-A+B)cos (- (A-B)/2)+sinC 由A+B+C=π有A+B=π-C (a)=-a=0;- (a^2)/2,;-1,√2,-1,a0. 为定值,此时C要最大必有A=B=C时sinA+sinB+sinC 取最大值即为2另一范围必在边界条件处确定,原式用正弦定理代替为:锐角三角形时, c2r ,直角三2r角形r=c/2 原式大于a+b+c=1+ (a+b)/c2 所以,2sinA+sinB+sinC≤ (3√3)/2 故答案 … Web2 dec. 2024 · Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto … proshares ultrashort dow30
trigonometry - Prove $ \sin (A+B)\sin (A-B)=\sin^2A …
WebHalo, Qiro'Atin K. Kakak bantu jawab ya. Jawaban untuk soal ini adalah -1/5 Ingat kembali rumus jumlah selisih dua sudut. sin(A - B) = sinA.cosB - cosA.sinB sin(A + B) = … Web8 jun. 2013 · 3SinB=sin2AcosB sinBcos2A 3=2sinAcosA/tanB 2cosAcosA-1 4(sinAsinA cosAcosA)=2sinAcosB/tanB 2cosAcosA 两边除以cosAcosA后在移几下用个公式就可以了 … WebQ state the formulae for the multiples and sub-multiples of angles such as cos2A, sin 2A, tan 2A, cos 3A, sin 3A, tan 3A, A A sin ,cos 2 2 and A tan 2; and Q solve simple … researching dogs